Upon balancing the equation what is the smallest possible integers that goes in front O₂? HBr + O₂ ➞ H₂O + Br₂ * 4 points 1 2 3 4

asked May 1, 2021 203k views

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Upon balancing the equation what is the smallest possible integers that goes in front O₂? HBr + O₂ ➞ H₂O + Br₂ *

4 points
1
2
3
4

by Zajke

6.5k points

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5 votes

1 because there would be equal oxygens on both sides

Anouar answered May 3, 2021

7.4k points

7 votes

Answer:

Step-by-step explanation:

4 HBr + O2 → 2H 20 + 2Br 2

...............

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