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How do these results about area and perimeter of similar quadrilaterals compare with similar situations for triangles?

User Marguerita
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2 Answers

4 votes

Answer:

Let's see

Explanation:

Two triangles are same ∆1 and ∆2

They have same height and breath

Now ∆1= ∆2

=> ar(∆1)= ar(∆2)

The same is for quadrilaterals

User Tony Blues
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5.6k points
4 votes
the ratio of the perimeters of similar figures is equal to their scale factor and that the ratio of their areas is equal to the square of their scale factor.
User Frant
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