Question

Kinetic energy of a body is increased by by 300% what is percentage increased in momentum

Answer 1

100% - double

200% - triple

300% - 4X

For a 300% increase the KE must be 4 time as large

KE2 / KE1 = M V2^2 / M V1^2 = (V1 / V2)^2 = 4

So V2 = 2 V1 for the requested increase

M V2 / M V1 = V2 / V1 = 2

So the momentum would double for a 100% increase