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a force F=600 N applied by a man on box and moves a distance d = 5m find the net work done on the box if the floor exerts a constant friction force of 20N

User Searock
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Answer:

Net work done = 2900 J

Step-by-step explanation:

Net force acting on box = f = 600N - 20N = 580N

Work done = force applied x distance moved

W = f x d

W = 580N x 5m

= 2900 J

Hope this helps!

User Niklascp
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