Question 1

Please help asap!!!

Rewrite the following equation as a function of x.

Question 2

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \:f(x)= 9280 - 20x$

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$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: \cfrac{1}{16} x + \cfrac{1}{320} y - 29 = 0$

$\qquad \tt \rightarrow \: \cfrac{1}{16} x + \cfrac{1}{320} y = 29$

$\qquad \tt \rightarrow \: \cfrac{20 x+ y}{320} = 29$

$\qquad \tt \rightarrow \: 20x + y = 29 \sdot320$

$\qquad \tt \rightarrow \: y = 9280 - 20x$

$\qquad \tt \rightarrow \: f(x) = 9280 - 20x$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Question 3

Answer:

B

Explanation:

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