Question

Any volunteer please help

Answer 1

Part A)

The equation in the point-slope form is:

`y-11=(4)/(3)\left(x-\left(-2\right)\right)`

Part B)

The graph of the equation is attached below.

Explanation:

Part A)

Given

• The point = (-2, 11)

• m = 4/3

The point-slope form of the line equation is

`y-y_1=m\left(x-x_1\right)`

Here, m is the slope and (x₁, y₁) is the point

substituting the values m = 4/3 and the point (-2, 11) in the point-slope form of the line equation

`y-y_1=m\left(x-x_1\right)`

`y-11=(4)/(3)\left(x-\left(-2\right)\right)`

Thus, the equation in the point-slope form is:

`y-11=(4)/(3)\left(x-\left(-2\right)\right)`

Part B)

As we have determined the point-slope form which passes through the point (-2, 11) and has a slope m = 4/3

The graph of the equation is attached below.