Question

1

An aeroplane of mass 2.5 x 105kg lands with a speed of 62 m/s, on a horizontal runway at time
t = 0. The aeroplane decelerates uniformly as it travels along the runway in a straight line until it
reaches a speed of 6.0 m/s at t = 35 s.
(a) Calculate:
(i) the deceleration of the aeroplane in the 35 s after it lands​

Answer 1

`a = -1.6\ m/s^2`

Step-by-step explanation:

Accelerated Motion

It occurs when an object changes its speed over time. If the changes in speed are uniform, then the acceleration is constant, positive if the speed increases, negative if the speed decreases.

The acceleration is calculated as follows:

`\displaystyle a=(v_f-v_o)/(t)`

The aeroplane starts with a speed of vo=62 m/s and reaches a speed of vf=6 m/s in t=35 s.

The acceleration is:

`\displaystyle a=(6-62)/(35)=-(56)/(35)`

`\mathbf{a = -1.6\ m/s^2}`