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39 votes
39 votes
Can someone plsss help me in this.

Can someone plsss help me in this.-example-1
User Alvin Rusli
by
2.7k points

2 Answers

14 votes
14 votes

Answer:


x \ = \ √(31) \ \text{m}

Explanation:

Since both triangles are right triangles, we then can leverage the Pythagorean Theorem.

Let the length of hypothenuse of the smaller triangle be
\gamma , hence


\gamma^(2) \ = a^(2) \ - \ b^(2) \\ \\ \gamma^(2) \ = \ \left(6\right)^(2) \ - \ \left(2\right)^(2) \\ \\ \gamma^(2) \ = \ 36 \ - \ 4 \\ \\ \gamma^(2) \ = \ 32

Subsequently,


\gamma^(2) \ = \ c^(2) \ + \ x^(2) \\ \\ \gamma^(2) \ - \ c^(2) = \ x^(2) \\ \\ x^(2) \ = \ 32 \ - \ \left(1\right)^(2) \\ \\ x^(2) \ = \ 32 \ - \ 1 \\ \\ x^(2) \ = \ 31 \\ \\ x \ = \ √(31)

User Skreborn
by
2.8k points
18 votes
18 votes

Answer:

first you need to find how long the side of the ab triangle is

so to find it you use the reciprocal Pythagorean theorem c2= a2-b2

so a2 -b2 = 6*6-2*2 = 30

so now we now that the side of the ab traingle is the square root of 30

then to find x you use the reciprocal Pythagorean theorem again and it goes x2= 30-c2

so x2= 30 -1*1 = 29

x = the square root of 29

Explanation:

that should do it

User Puru
by
3.2k points
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