Question

Vince went on a 3 day hiking trip, he walked 3/4 the distance that he walked the day before. He walked 83.25 kilometers total in the trip. How far did Vince walked on the 1st day of the trip ?

Answer 1

36

Explanation:

Answer 2

Vince walked 36 km on the 1st day of the trip.

Explanation:

• Vince went on a 3-day hike trip.

• It is stated that Vince walks 3/4 of the distance that he walks the day before.

• His total traveled distance = 83.25

• Let 'x' be the distance traveled on the first day.

As he walks 3/4 of the distance that he walks the day before.

• so the second-day traveling distance = 3/4x

• And the third-day traveling distance = 3/4 × 3/4x

= 9/16x

Given his total traveled distance = 83.25

Therefore, the equation becomes

`x\:+\:(3)/(4)x\:+\:(9)/(16)x\:\:=\:83.25`

Multiply both sides the 16 (L.C.M)

`x\cdot \:16+(3)/(4)x\cdot \:16+(9)/(16)x\cdot \:16=83.25\cdot \:16`

simplify

`16x+12x+9x=1332`

`37x=1332`

Divide both sides by 37

`(37x)/(37)=(1332)/(37)`

`x=36` km

Therefore, Vince walked 36 km on the 1st day of the trip.