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Calculate the number of molecules in 895 g of H2O.

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Answer:

The number of molecules in 895 g of H₂O is 4.49*10²⁵.

Step-by-step explanation:

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number represents a quantity without an associated physical dimension, so it is considered a pure number that allows describing a physical characteristic without an explicit dimension or unit of expression. Avogadro's number applies to any substance.

In this case, the molar mass of compound H₂O is 18 g / mol. So if 18 grams of H₂O are present in 1 mole, 895 grams will be present in how many moles of H₂O?


moles of H_(2)O=(895 grams*1 mole )/(18 grams)

moles of H₂O= 74.58

Then the following rule of three can be applied: if 1 mole of the compound contains 6.023 * 10²³ molecules by definition of Avogadro's number, 74.58 moles of the compound how many molecules will it contain?


amount of molecules=(74.58 moles*6.023*10^(23)molecules )/(1 mole)

amount of molecules=4.49*10²⁵

The number of molecules in 895 g of H₂O is 4.49*10²⁵.

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