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4.18 L of oxygen, O2, at STP is how many molecules of O2?

User Mike Davis
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1 Answer

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Answer:

1.12 × 10²³ molecules O₂

General Formulas and Concepts:

Chemistry - Atomic Structure

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Step-by-step explanation:

Step 1: Define

4.18 L O₂

Step 2: Identify Conversions

Avogadro's Number

STP - 22.4 L / mol

Step 3: Convert


4.18 \ L \ O_2((1 \ mol \ O_2)/(22.4 \ L \ O_2))((6.022 \cdot 10^(23) \ molecules \ O_2)/(1 \ mol \ O_2) ) = 1.12375 × 10²³ molecules O₂

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

1.12375 × 10²³ molecules O₂ ≈ 1.12 × 10²³ molecules O₂

User Ergunkocak
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