Question

15 point hurry

In the following function defined by an equation in the form y = a x squared + b x + c, identify the values of a, b, and c.
y = two-thirds x squared + 3
a.
a = 0, b = two-thirds, c = 3
b.
a = two-thirds, b = 0, c = 3
c.
a = 0, b = 3, c = two-thirds
d.
a = two-thirds, b = two-thirds, c = 3

Answer 1

Given:

`y=(2)/(3)x^2+3`

This equation is in the form
`y=ax^2+bx+c`.

To find:

The values of a, b and c.

Solution:

We have,

`y=(2)/(3)x^2+3`

It can be written as

`y=(2)/(3)x^2+(0)b+3`

On comparing this equation with
`y=ax^2+bx+c`, we get

`a=(2)/(3),b=0,c=3`

Therefore, the correct option is b.