Question

Chemistry Question, Don't really know how to do it lol.

Answer 1

Answer: 17.2 g

Step-by-step explanation:

To calculate the moles :

`\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}`

`\text{Moles of} HgS=(20.0 g)/(233g/mol)=0.085moles`

The balanced chemical equation is:

`4HgS(s)+4CaO(s)\rightarrow 4Hg(l)+3CaS(s))+CaSO_4(s)`

According to stoichiometry :

4 moles of
`HgS` produce = 4 moles of
`Hg`

Thus 0.085 moles of
`HgS` will require=
`(4)/(4)* 0.085=0.085moles` of
`Hg`

Mass of
`Hg=moles* {\text {Molar mass}}=0.085moles* 200.6g/mol=17.2g`

Thus 17.2 g of
`Hg` will be produced form 20.0 g of HgS.