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I need help with math homework

I need help with math homework-example-1
User Purrell
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1 Answer

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Answer:

A. (1, 2) and (4, 3)

B. Slope (m) = ⅓

C. y - 2 = ⅓(x - 1)

D.
y = (1)/(3)x + (5)/(3)

E.
-(1)/(3)x + y = (5)/(3)

Explanation:

A. Two points on the line from the graph are: (1, 2) and (4, 3)

B. The slope can be calculated using two points, (1, 2) and (4, 3):


slope (m) = (y_2 - y_1)/(x_2 - x_1) = (3 - 2)/(4 - 1) = (1)/(3)

Slope (m) = ⅓

C. Equation in point-slope form is represented as y - b = m(x - a). Where,

(a, b) = any point on the graph.

m = slope.

Substitute (a, b) = (1, 2), and m = ⅓ into the point-slope equation, y - b = m(x - a).

Thus:

y - 2 = ⅓(x - 1)

D. Equation in slope-intercept form, can be written as y = mx + b.

Thus, using the equation in (C), rewrite to get the equation in slope-intercept form.

y - 2 = ⅓(x - 1)

3(y - 2) = x - 1

3y - 6 = x - 1

3y = x - 1 + 6

3y = x + 5


y = (1)/(3)x + (5)/(3)

E. Convert the equation in (D) to standard form:


y = (1)/(3)x + (5)/(3)


-(1)/(3)x + y = (5)/(3)

User NotAName
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