Question

I need help with math homework algebra #4

Answer 1

A. (-5, 0) and (1, -3)

B. Slope (m) = -½

C. y + 3 = -½(x - 1)

D. y = -½x - ⁵/2

E. ½x + y = ⁵/2

Explanation:

A. Two points on the line from the graph are: (-5, 0) and (1, -3)

B. The slope can be calculated using two points,(-5, 0) and (1, -3):

`slope (m) = (y_2 - y_1)/(x_2 - x_1) = (-3 - 0)/(1 -(-5)) = (-3)/(6) = -(1)/(2)`

Slope (m) = -½

C. Equation in point-slope form is represented as y - b = m(x - a). Where,

(a, b) = any point on the graph.

m = slope.

Substitute (a, b) = (1, -3), and m = -½ into the point-slope equation, y - b = m(x - a).

Thus:

y - (-3) = -½(x - 1)

y + 3 = -½(x - 1)

D. Equation in slope-intercept form, can be written as y = mx + b.

Thus, using the equation in (C), rewrite to get the equation in slope-intercept form.

y + 3 = -½(x - 1)

2(y + 3) = -1(x - 1)

2y + 6 = -x + 1

2y = -x + 1 - 6

2y = -x - 5

y = -x/2 - ⁵/2

y = -½x - ⁵/2

E. Convert the equation in (D) to standard form:

y = -½x - ⁵/2

½x + y = ⁵/2