Question

What is the molarity of sulfuric acid if 25.0 ml of the solution is neutralized by 25.5 ml of 0.50 M KOH?

Answer 1

[H₂SO₄] = 0.255M

Step-by-step explanation:

H₂SO₄ + 2KOH => K₂SO₄ + 2H₂O

2(M x V)acid = (M x V)base => M(acid) = (M x V)base /2·Vacid

[H₂SO₄] = (0.5M)(25.5ml)/2(25.0ml) = 0.255M