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What is the approximate energy of a photon having a frequency of 4X10^14 Hz? (h= 6.6X10-34 Js)
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What is the approximate energy of a photon having a frequency of 4X10^14 Hz? (h= 6.6X10-34 Js)

User Justabuzz
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1 Answer

3 votes

Answer:

2.65 x 10⁻¹⁹ J

Step-by-step explanation:

ΔE = h·f = (6.63 x 10⁻³⁴J·s)(4 x 10¹⁴s⁻¹) = 2.65 x 10⁻¹⁹ J

User Amen Ra
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