Question

A dog sits 1.50m from the center of the merry-go-around and revolves at a tangential speed of 1.80m\s. If the dog’s mass is 18.5kg, what is the magnitude of the centripetal force on the dog?

A) 25.53n
B) 32.51n
C) 39.96n
D) 42.55n

Answer 1

39.96 N

Further explanation:

Given

radius=R=1.5 m

Tangential speed =v=1.80m\s

mass of the dog=18.5 kg

Required

The magnitude of the centripetal force

Analysis

Use Centripetal force formula :

`]\large{\boxed{\bold{F= (mv^2)/(R)}}`

F = centripetal force , N

m = mass , Kg

v = linear velocity/tangential , m/s

r = radius , m

Solution

`\tt F=(18.5* 1.8^2)/(1.5)\\\\F=39.96~N`

Paraphrase

The magnitude of the centripetal force on the dog : 39.96 N