Question

Question

Find the equation of the line that is perpendicular to the given line and passes through the given point.
Enter your answer in slope-intercept form (y = mx + b ) with the values of m and b given as decimals,
rounded to the nearest hundredth if necessary.
y = 10x ; (6,-4)
The equation is y =





PLEASE ANSWER QUICKLY !!!

Answer 1

y = -0.1x - 3.4

Explanation:

The point-slope form of equation of a line is:

y - y₀ = m(x - x₀)

where (x₀, y₀) is the point which the line passes through and m is the slope of the line

The product of slopes of two perpendicular lines is -1

so if given lines slope is 10 them:

10·m = -1

m = -0.1

(6, -4) ⇒ x₀ = 6, y₀ = -4

Therefore:

y - (-4) = -0.1(x - 6)

y = -0.1x + 0.6 + (-4)

y = -0.1x - 3.4