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5(x-3)(x+1) what possible value of x satisfies the equation above

User Stormenet
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1 Answer

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To start, let's use algebra to solve this equation for x:

2ax-15=3(x+5)+5(x-1)

2ax - 15 = 3x + 15 + 5x - 5

2ax - 15 = 8x +10

(2a - 8)x = 25

x = 25/(2a-8)

The only way that this equation does not have a solution is if 2a - 8 = 0, as that would mean x = 25/0, and we can't divide by 0. If 2a - 8 = 0, then a = 4. And so the original equation, 2ax-15=3(x+5)+5(x-1) will not have a solution when a = 4.

User Mateostabio
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