Question

HELP :O >>>>Write an equation of the line passing through the point (5, 2) that is perpendicular to the line −x+3y=12.

The equation of the line is y= x+

Answer 1

y - 2 = -3(x - 5)

Explanation:

Solving the given −x+3y=12. for 3y yields 3y = x + 12, which becomes

x + 12

y = -------------

3

and so we see that the slope of the given line is 1/3. Thus the slope of any line which is perpendicular to this one is the negative reciprocal of 1/3, or -3.

Use the point-slope form of the equation of a straight line and the given point (5, 2) to find the desired equation:

y - k = m(x - h) becomes y - 2 = -3(x - 5)