Question

A chemical reaction in a lab experiment actually produces 1.23mol of BeBr2. The theoretical yield is 220g. To two decimal places, what is the percentage yield

Answer 1

Percent yield = 94.62%

Step-by-step explanation:

Given data:

Actual yield of BeBr₂ = 1.23 mol

Theoretical yield of BeBr₂ = 220 g

Percent yield = ?

Solution:

Theoretical yield in moles:

Number of moles = mass/molar mass

Number of moles = 220 g/168.82 g/mol

Number of moles = 1.30 mol

Percent yield:

Percent tiled = actual yield / theoretical yield × 100

by putting values,

Percent yield = 1.23 mol / 1.30 mol × 100

Percent yield = 0.9462 × 100

Percent yield = 94.62%