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A cannonball with a perfect horizontal velocity of 50.0 m/s flies 350 m before hitting the

ground. How much time was the cannonball in the air? Remember t d/v
05s
O 10s
35 s
7s

1 Answer

1 vote

Answer:

7 s

Step-by-step explanation:

The time taken can be found by using the formula


t = (d)/(v) \\

d is the distance

v is the velocity

From the question we have


t = (350)/(50) = (35)/(5) = 7 \\

We have the final answer as

7 s

Hope this helps you

User Winter
by
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