Question

Is there anything after 16a+20 ?

Answer 1

The equivalent expressions are:

`4\left(4a+5\right)=16a+20`

`=2\left(8a+10\right)`

`=12a+20+4a`

Yes, 16a+20 could be further reduced by taking 2 as a common factor.

i.e. 16a+20 = 2(8a+10)

Explanation:

Given the expression

• 
  `4(4a+5)`

solving the expression to determine the equivalent expression

`4\left(4a+5\right)`

`\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac`

`4\left(4a+5\right)=4\cdot \:\:4a+4\cdot \:\:5`

`=16a+20`

Taking 2 as the common factor

`=2\left(8a+10\right)`

Also

`12a+20+4a = 16a+20`

Therefore, the equivalent expressions are:

`4\left(4a+5\right)=16a+20`

`=2\left(8a+10\right)`

`=12a+20+4a`

Yes, 16a+20 could be further reduced by taking 2 as a common factor.

i.e. 16a+20 = 2(8a+10)