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Solve this please kkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk

Solve this please kkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk-example-1
User Linimin
by
4.0k points

2 Answers

6 votes

Answer: ↔ sinD × cosD

↔ sinC

↔ cosC × tanD

↔ sinD

Step-by-step explanation:

In the given triangle CBD

∵ ∠B is a right angle

∴ CD is the hypotenuse

→ We can use the trigonometry ratios

∵ sinC = opposite side of ∠C ÷ hypotenuse

∴ sinC =

∵ BD = 3 and CD = 5

∴ sinC =

∵ cosC = adjacent side of ∠C ÷ hypotenuse

∴ cosC =

∵ BC = 4 and CD = 5

∴ cosC =

∵ tanC = opposite side of ∠C ÷ adjacent side of ∠C

∴ tanC =

∵ BD = 3 and BC = 4

∴ tanC =

∵ sinD = opposite side of ∠D ÷ hypotenuse

∴ sinD =

∵ BC = 4 and CD = 5

∴ sinD =

∵ cosD = adjacent side of ∠D ÷ hypotenuse

∴ cosD =

∵ BD = 3 and CD = 5

∴ cosD =

∵ tanD = opposite side of ∠D ÷ adjacent side of ∠D

∴ tanD =

∵ BD = 3 and BC = 4

∴ tanD =

Let us find the answer to each tile

→ sinD = ⇒ 4th answer

→ sinC = ⇒ 2nd answer

→ sinD × cosD = ( ) × () = ⇒ 1st answer

→ tanC × tanD = × = 1 ⇒ Not used

→ cosC × tanD = × = ⇒ 3rd answer

Explanation:

User Bwyss
by
4.3k points
0 votes

Answer:


(12)/(25)sinD × cosD


(3)/(5)sinC


(16)/(15)cosC × tanD


(4)/(5)sinD

Explanation:

In the given triangle CBD

∵ ∠B is a right angle

∴ CD is the hypotenuse

→ We can use the trigonometry ratios

∵ sinC = opposite side of ∠C ÷ hypotenuse

∴ sinC =
(BD)/(DC)

∵ BD = 3 and CD = 5

∴ sinC =
(3)/(5)

∵ cosC = adjacent side of ∠C ÷ hypotenuse

∴ cosC =
(BC)/(DC)

∵ BC = 4 and CD = 5

∴ cosC =
(4)/(5)

∵ tanC = opposite side of ∠C ÷ adjacent side of ∠C

∴ tanC =
(BD)/(BC)

∵ BD = 3 and BC = 4

∴ tanC =
(3)/(4)

∵ sinD = opposite side of ∠D ÷ hypotenuse

∴ sinD =
(BC)/(DC)

∵ BC = 4 and CD = 5

∴ sinD =
(4)/(5)

∵ cosD = adjacent side of ∠D ÷ hypotenuse

∴ cosD =
(BD)/(DC)

∵ BD = 3 and CD = 5

∴ cosD =
(3)/(5)

∵ tanD = opposite side of ∠D ÷ adjacent side of ∠D

∴ tanD =
(BC)/(BD)

∵ BD = 3 and BC = 4

∴ tanD =
(4)/(3)

Let us find the answer to each tile

sinD =
(4)/(5)4th answer

sinC =
(3)/(5)2nd answer

sinD × cosD = (
(4)/(5)) × (
(3)/(5)) =
(12)/(25) ⇒ 1st answer

→ tanC × tanD =
(3)/(4) ×
(4)/(3) = 1 ⇒ Not used

cosC × tanD =
(4)/(5) ×
(4)/(3) =
(16)/(15) ⇒ 3rd answer

User Abel
by
3.5k points