Answer: ↔ sinD × cosD
↔ sinC
↔ cosC × tanD
↔ sinD
Step-by-step explanation:
In the given triangle CBD
∵ ∠B is a right angle
∴ CD is the hypotenuse
→ We can use the trigonometry ratios
∵ sinC = opposite side of ∠C ÷ hypotenuse
∴ sinC =
∵ BD = 3 and CD = 5
∴ sinC =
∵ cosC = adjacent side of ∠C ÷ hypotenuse
∴ cosC =
∵ BC = 4 and CD = 5
∴ cosC =
∵ tanC = opposite side of ∠C ÷ adjacent side of ∠C
∴ tanC =
∵ BD = 3 and BC = 4
∴ tanC =
∵ sinD = opposite side of ∠D ÷ hypotenuse
∴ sinD =
∵ BC = 4 and CD = 5
∴ sinD =
∵ cosD = adjacent side of ∠D ÷ hypotenuse
∴ cosD =
∵ BD = 3 and CD = 5
∴ cosD =
∵ tanD = opposite side of ∠D ÷ adjacent side of ∠D
∴ tanD =
∵ BD = 3 and BC = 4
∴ tanD =
Let us find the answer to each tile
→ sinD = ⇒ 4th answer
→ sinC = ⇒ 2nd answer
→ sinD × cosD = ( ) × () = ⇒ 1st answer
→ tanC × tanD = × = 1 ⇒ Not used
→ cosC × tanD = × = ⇒ 3rd answer
Explanation: