1 Answer

Andrew Axton · Answer 1 · 2021-11-21T15:41:24+0000

1.563 g

Given

A half life of 2.5 days ⇒ t1/2 = 2.5 days

initial sample ⇒ 25 g

duration of decay ⇒ 10 days

Required

sample left after 10 days

Analysis

Use decay Formula :

$\tt Nt=No.(1)/(2)^(T/t1/2)$

Solution

$\tt Nt=25.(1)/(2)^(10/2.5)\\\\Nt=25.(1)/(2)^4\\\\Nt=\boxed{\bold{1.563~g}}$

Paraphrase

Substance left after 10 days = 1.563 g

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