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A compound has a molecular mass of 54 and an empirical formula of C2H3. What is the molecular formula of the compound?

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Answer:

C₄H₆

Step-by-step explanation:

The empirical formula of the compound is given as;

C₂H₃

Now find the molecular mass of the empirical formula first;

C₂H₃ = 2(12) + 3(1) = 27g/mol

Since the molecular mass of the true compound is 54,

Ratio of the molecular formula to empirical formula = 54/27 = 2

Molecular formula = 2( C₂H₃ ) = C₄H₆

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