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Solve the system of equations.

y = -2x + 5
y = x^2 + 3x +9
a. (-1,7), (-4,13)
b. (-1,-3), (-4,3)
c. (-1,13), (-4, 7)
d. (1,3), (4,13)

Solve the system of equations. y = -2x + 5 y = x^2 + 3x +9 a. (-1,7), (-4,13) b. (-1,-3), (-4,3) c-example-1
User Kia Kaha
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2 Answers

13 votes
The answer should be The B
User Hamid Pourjam
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9 votes

Answer:

A

Explanation:

y = - 2x + 5 → (1)

y = x² + 3x + 9 → (2)

substitute y = x² + 3x + 9 into (1)

x² + 3x + 9 = - 2x + 5 ( subtract - 2x + 5 from both sides )

x² + 5x + 4 = 0 ← in standard form

(x + 1)(x + 4) = 0 ← in factored form

equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

x + 4 = 0 ⇒ x = - 4

substitute these values into (1) for corresponding values of y

x = - 1 : y = - 2(- 1) + 5 = 2 + 5 = 7 ⇒ (- 1, 7 )

x = - 4 : y = - 2(- 4) + 5 = 8 + 5 = 13 ⇒ (- 4, 13 )

User ShowFocus
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