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If 2^(3x) = 1/8 & 10^y=0.001: then 3^(-x)5^(-y) = ?​
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If 2^(3x) = 1/8 & 10^y=0.001: then 3^(-x)5^(-y) = ?​

User XjeaxaxX
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1 Answer

9 votes

Answer:

32.

Explanation:

2^3x=2^-3. (1/8=2^-3). 3x=-3. x=-1. 10^y=10^-3. y=-3. 3-(-1).5-(-3). 3+1.5+3.

User Barry Holroyd
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