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I need some serious help with some problems there are some on my profile and this one

I need some serious help with some problems there are some on my profile and this-example-1
User Iisystems
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Answer:

a) 28

b) D

Explanation:

a) As you can see from the diagram, in a 60-30 right triangle, the side adjacent to the 60° angle is half of the hypotenuse.

14*2=28

b) If you remember your SohCahToa, then you'll know that your trigonometric functions are:


sin = (opp)/(hyp)\\cos = (adj)/(hyp)\\tan = (sin)/(cos)

Now we can check each one to find the incorrect ratio:


sin (30^o)=(4)/(8)=(4)/(8)\\cos(60^o)=(4)/(8)=(4)/(8)\\sin(60^o)=(√(48))/(8)=(√(48))/(8)\\tan(30^o)=(4)/(√(48))\\eq (√(48))/(8)

I need some serious help with some problems there are some on my profile and this-example-1
User Bluefin
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