Question

I need some serious help with some problems there are some on my profile and this one

Answer 1

a) 28

b) D

Explanation:

a) As you can see from the diagram, in a 60-30 right triangle, the side adjacent to the 60° angle is half of the hypotenuse.

14*2=28

b) If you remember your SohCahToa, then you'll know that your trigonometric functions are:

`sin = (opp)/(hyp)\\cos = (adj)/(hyp)\\tan = (sin)/(cos)`

Now we can check each one to find the incorrect ratio:

`sin (30^o)=(4)/(8)=(4)/(8)\\cos(60^o)=(4)/(8)=(4)/(8)\\sin(60^o)=(√(48))/(8)=(√(48))/(8)\\tan(30^o)=(4)/(√(48))\\eq (√(48))/(8)`