Question

Solve the system by substitution.
4y =
5x -10y =-50

Answer 1

`x = -20 ; y =-5`

Explanation:

Eqn. 1 ----> 4y = x

Eqn. 2 ----> 5x-10y = -50

(Simplifying eqn.2 further)

`=>5(x-2y)=-50`

`=>x-2y=(-50)/(5) =-10`

(Substituting the value of x from eqn. 1)

`=>4y-2y=-10`

`=>2y=-10`

`=>y =(-10)/(2) =-5`

Now, substituting the value of y in eqn. 1 ,

`x = 4*(-5)=-20`