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What is the slope-intercept equation of the line that goes through the points (3,5) and (-1,13)

User Natoya
by
6.4k points

1 Answer

4 votes

Answer:

y=-2x+11

Explanation:

Slope-intercept form is y=mx+b.

Slope is rise/run, which is y2-y1/x2-x1. Using these points, that's (13-5)/(-1-3). This is 8/-4, or -2.

You can plug this into y=mx+b to get y=-2x+b.

To solve for b, you can use one of the original points and plug it back into the formula:

y=-2x+b

5=-2(3)+b

5=-6+b

b=11

So, putting it all together, you get y=-2x+11.

User Martin Baulig
by
6.6k points
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