Answer:
a) 2.5secs
b) 31.25m
Step-by-step explanation:
a) From the question, we are given;
Initial speed u = 15m/s
Final speed v = 10.0m/s
Acceleration =-2.0m/s²
Required
How long it takes take the car to accelerate (Time t)
Using the equation of motion
v = u+ at
10 = 15+(-2)t
10 = 15-2t
10-15 = -2t
-5 = -2t
t = 5/2
t = 2.5secs
Hence it takes the car 2.5secs to accelerates.
b) We are to find distance S
Using the equation
S = ut + 1/2at²
S = 15(2.5)+1/2(-2)(2.5)²
S = 37.5-6.25
S = 31.25m
Hence the car as moved by 31.25m during the breaking period.