Answer:
96
Explanation:
Given that :
Standard deviation (s) = 2km
Error in estimation is within 0.4 km ; Error (E) = 0.4 km
Using the relation :
Sample size = ((Zα/2 * s) /E)^2
Using α = 0.05
The Zcritical at 0.05 = Z0.025 = 1.96
Sample size = ((1.96 * 2) / 0.4)^2
Sample size = (3.92 / 0.4)^2
Sample size = 9.8²
Sample size = 96.04
Required sample size = 96