Question

Can someone help me and make a code for this in PYTHON, please? I would be very grateful!

It is estimated that China on July 1, 2019. had 1,420,062,022 inhabitants. The population of China increases by 0.35% every year. Assuming that the annual population growth in China will not change, show the expected population of China in the next ten years.
Please... Thanks in advance!

Answer 1

The expected population of China over the next ten years can be calculated using a Python program, taking into account an annual growth rate of 0.35% applied to the starting population figure from July 1, 2019.

Step-by-step explanation:

To calculate the expected population of China in the next ten years based on a starting population of 1,420,062,022 and an annual growth rate of 0.35%, we can use a simple Python program.

We'll use the formula for compound interest to calculate the population each year:

future_population = current_population * (1 + growth_rate)^number_of_years

Here's the Python code snippet:

# Starting population of China on July 1, 2019
population = 1420062022
# Annual growth rate
growth_rate = 0.0035

# Calculate expected population over the next ten years
for year in range(1, 11):
population = population * (1 + growth_rate)
print("Year", year, ":", round(population))

This code will output the population for each year from 2020 to 2029, rounding off to the nearest whole number as population counts are typically whole numbers.

Answer 2

Code:

next_ten_years = 1420062022*1.0035**10

print(next_ten_years)

Output:

1470554353.1178253

Step-by-step explanation:

Since the population of inhabitants increases by
`0.35\%` each year, the total population must be
`100.35\%` of the previous year's population (since it includes the previous size of the population and the
`0.35\%` increase of the population)

The math:

Expected population in next 10 years =
`1420062022 * 1.0035^(10)` (
`100.35\%` is
`1.0035`)

Code:

Looking at the code above, the '**' raises the power of a number to the number you put after the operator, so 1.0035**10 is
`1.0035^(10)`. The '*' operator multiplies the two numbers that are placed before and after the operator, so 1420062022*1.0035 is
`1420062022* 1.0035`.

The expected population in the next ten years is 1,470,554,353 (if we round to the nearest inhabitants since there can't be a decimal amount of inhabitants).

Hope this helps :)