Question

B. How many moles of oxygen are needed to produce 9 moles of water in the combustion of ethane?

Answer 1

C2H6 + 7/2 O2-----------> 2CO2 + 3H2OMultipying the above Equation throughout by 3, we get3 C2H6 + 21/2 O2-------->6 CO2+ 9 H2OFrom the above equation it is clear that in the combustion of Ethane, 10.5- moles of oxygen is (336 g) required to produce 9- moles of water.

Answer 2

answer

From the above equation it is clear that in the combustion of Ethane, 10.5- moles of oxygen is (336 g) required to produce 9- moles of water.

Step-by-step explanation:

C2H6 + 7/2 O2-----------> 2CO2 + 3H2O

Multipying the above Equation throughout by 3, we get

3 C2H6 + 21/2 O2-------->6 CO2+ 9 H2O