Question

Reverse percentages question.

during a promotion a bag of sweets contain 20% extra free.There are 24 sweets in the bag during the promotion.

How many sweets are there normally?

Answer 1

Given:

During a promotion a bag of sweets contain 20% extra free.

Sweets in the bag during the promotion = 24

To find:

The number of sweets are there normally.

Solution:

Let x be the number of sweets are there normally.

Then, number of sweets during the promotion is 20% more than x.

`=x+(20)/(100)* x`

`=x+(1)/(5)x`

`=(5x+x)/(5)`

`=(6x)/(5)`

Sweets in the bag during the promotion = 24

`(6x)/(5)=24`

Multiply both sides by 5.

`6x=120`

Divide both sides by 6.

`x=20`

Therefore, normally there are 20 number of sweets.