Answer:
the product of the given radical is
![\sqrt[5]{12}](https://img.qammunity.org/2021/formulas/mathematics/high-school/vvk8bqccnikph9oe7o3985ga5jcgwa5695.png)
Explanation:
The computation of the product of the given radicals is as follows
According to the question, the following radical is
![√(50) \ and \sqrt[5]{6}](https://img.qammunity.org/2021/formulas/mathematics/high-school/za5qojldc3q7ox3hnv8ubc5w0uf6yxx2fk.png)
Now simplify it
![√(25 * 2) and \sqrt[5]{6}\\\\√(25) √(2) and \sqrt[5]{6}\\\\\sqrt[5]{2} and \sqrt[5]{6}\\\\\sqrt[5]{12}](https://img.qammunity.org/2021/formulas/mathematics/high-school/npuls03ju4cwxn8sb23pf0acr716rydxgh.png)
Hence, the product of the given radical is
![\sqrt[5]{12}](https://img.qammunity.org/2021/formulas/mathematics/high-school/vvk8bqccnikph9oe7o3985ga5jcgwa5695.png)
This is the answer but the same is not given in the options