Question

The picture. and answer 1-6. please hurry

Answer 1

Explanation:

From the figure attached,

1). Sin(D) =
`\frac{\text{Opposite side}}{\text{Hypotenuse}}`

=
`(EF)/(DF)`

=
`(24)/(26)`

=
`(12)/(13)`

2). Cos(D) =
`\frac{\text{Adjacent side}}{\text{Hypotenuse}}`

=
`(ED)/(DF)`

=
`(10)/(26)`

=
`(5)/(13)`

3). tan(D) =
`\frac{\text{Opposite side}}{\text{Adjacent side}}`

=
`(EF)/(DE)`

=
`(24)/(10)`

=
`(12)/(5)`

4). sin(F) =
`\frac{\text{Opposite side}}{\text{Hypotenuse}}`

=
`(DE)/(DF)`

=
`(10)/(26)`

=
`(5)/(13)`

5). cos(F) =
`\frac{\text{Adjacent side}}{\text{Hypotenuse}}`

=
`(EF)/(DF)`

=
`(24)/(26)`

=
`(12)/(13)`

6). tan(F) =
`\frac{\text{Adjacent side}}{\text{Adjacent side}}`

=
`(DE)/(EF)`

=
`(10)/(24)`

=
`(5)/(12)`