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23 votes
Solve the following system of equations and show all work.

y = 2x2
y =
3x -1 (10 points)

1 Answer

9 votes

Answer:
\left((1)/(2), 1 \right), (1, 2)

Explanation:

We have
y=2x^(2) and
y=3x-1.

Since both of the equations are set equal to y, we can conclude that:


2x^2 = 3x-1\\\\2x^(2)-3x+1=0\\\\(2x-1)(x-1)=0\\\\x=(1)/(2), 1

If
x=(1)/(2), then
y=3\left((1)/(2) \right)-1=1

If
x=1, then
y=3-1=2

Therefore, the solutions are
\left((1)/(2), 1 \right), (1, 2)

User Ananda
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