⠀⠀⠀⠀⠀⠀☆☞Diagram☜☆
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
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______________________________
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AnswEr :
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➤ How to solve ?
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For solving such problems we need to recall some rules and properties of quadrilateral .
Above given figure is a figure of an rectangle . We know that the diagonals of an rectangle bisect each other
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Bisect is refer to dividing the line into 2 equal parts .
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From this property of the rectangle ; we can observe in the given rectangle that
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⠀⠀⠀⠀⠀⠀⠀⠀AE = EC
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Solution :
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As , AE = EC
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➠ x + 11 = 6x + 1
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➠ x - 6x = 1 - 11
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➠ -5x = - 10
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➠ 5x = 10
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➠ x = 10/5
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➠ x = 2
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∴ The value of x is 2 .
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