Question

Using Newton's Method, what is the formula for determining the nth term in a sequence of approximations to a solution of a polynomial equation

Answer 1

Explanation:

in newton rapson method

`x_(n+1)=x_(n)-(f\left(x_(n)\right))/(f^(\prime)\left(x_(n)\right))`

Let
`n=n-1`

`x_((n-1)+1)=x_(n-1)-(f\left(x_(n-1)\right))/(f^(\prime)\left(x_(n-1)\right))`

`x_(n)=x_(n-1)-(f\left(x_(n-1)\right))/(f^(\prime)\left(x_(n-1)\right))`