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A parallelogram has vertices at A(-8, 5), B(10, 3), C(1, -5) and D(-4, -3). Find the coordinates of the figure after a dilation with a scale factor of 5

2 Answers

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where are you going on a
User Extrabacon
by
5.3k points
2 votes

The new coordinates are given as;

A' = (-40, 25)

B' = (50, 15)

C' = (5, -25)

D' = (-20, -15)

To find the coordinates of the parallelogram after a dilation with a scale factor of 5, we can simply multiply each original coordinate by 5:

Original coordinates:

A = (-8, 5)

B = (10, 3)

C = (1, -5)

D = (-4, -3)

Dilated coordinates:

A' = (-8× 5, 5 × 5) = (-40, 25)

B' = (10 × 5, 3 × 5) = (50, 15)

C' = (1 × 5, -5 × 5) = (5, -25)

D' = (-4× 5, -3 × 5) = (-20, -15)

Therefore, the dilated parallelogram has its vertices at:

A' = (-40, 25)

B' = (50, 15)

C' = (5, -25)

D' = (-20, -15)

User Jspizziri
by
4.8k points
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