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The Johnsons’ new swimming pool measures 3x^2-2x+1 ft in length and x+2 ft in width. What is the area of the new swimming pool, in square feet?

User Yakima
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1 Answer

8 votes

Answer:


3x^3 + 4x^2 -3x + 2

Explanation:

The area of the swimming pool will be equal to
length * width.

We know that the length is
3x^2-2x+1 and the width is
x+2.

Therefore we can substitute those into the equation:


(3x^2-2x+1)(x+2)\\

Then, we expand the brackets using a grid (attached).

After this, we collect like terms to find the final answer:


3x^3+6x^2-2x^2-4x+x+2\\3x^3 + 4x^2 -3x + 2

Our final answer is:
3x^3 + 4x^2 -3x + 2

The Johnsons’ new swimming pool measures 3x^2-2x+1 ft in length and x+2 ft in width-example-1
User Adam Cherti
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