Question

If 3x^2 + y^2 = 7 then evaluate the second derivative of y with respect to x when x = 1 and y = 2. Round your answer to 2 decimal places. Use the hyphen symbol, -, for negative values.

Answer 1

Answer:-21/8

Explanation:

3x^2 + y^2 = 7

6x dx + 2y dy = 0

dy/dx = -3x/y

at (1,2) = -3/2

d^2y/dx^2 = (-3y +3 x (dy/dx))/ y^2

at (1,2) = (-6 + 3(-3/2) / 4

(-6-9/2)/4

-21/8