31 is two standard deviations below the mean, since
31 = 35 - 4 = 35 - 2×2
33 is one standard deviation below the mean, since
33 = 35 - 2
So, we have

where
has the given normal distribution (mean 35, s.d. 2) and
has the standard normal distribution (mean 0, s.d. 1).
Recall the empirical (68-95-99.7) rule, which says
The normal distribution is also symmetric about its mean, so
Now,

so the 351 values between 31 and 33 make up about 13.5% of the total body of data in the distribution. Then there must be

values in the whole data set. (A)