Question

(-2)^-3 x (-3)^-2 Pls help me solve

Answer 1

`-(1)/(72)`

Explanation:

We can solve this by using laws of indices.

To start, laws of indices state:

`x^(-y) = (1)/(x^y)`

So, let's firstly take the first part of the sum =
`-2^(-3)`

According to the law shown above:

`-2^(-3) = (1)/(-2^3) = (1)/(-8) = -(1)/(8)`

Let's now take the second part of the sum =
`-3^(-2)`

According to the law shown above:

`-3^(-2) = (1)/(-3^2) = (1)/(9)`

Finally, the sum tells us to multiply those two values together, so we do so:

`-(1)/(8) * (1)/(9) = -(1)/(72)`

Therefore, our final answer is
`-(1)/(72)`.