Answer:



Therefore,
Option (A) is false
Option (B) is false
Option (C) is false
Explanation:
Considering the graph
Given the vertices of the segment AB
Finding the length of AB using the formula







units
Given the vertices of the segment JK
From the graph, it is clear that the length of JK = 5 units
so
units
Given the vertices of the segment GH
Finding the length of GH using the formula





![\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0](https://img.qammunity.org/2021/formulas/mathematics/high-school/ffxqfy16n523ob6t30evmdn0ppabjicbmg.png)
units
Thus, from the calculations, it is clear that:
Thus,



Therefore,
Option (A) is false
Option (B) is false
Option (C) is false