Question

What is the midpoint between -2-3i and 3+9i

Answer 1

1/2 + 3i is the midpoint between -2-3i and 3+9i.

Explanation:

Given the complex number

• -2-3i

• 3+9i

The formula to find the midpoint of two complex number (a + bi) and (c + di) is:

`M=(\left(a+c\right))/(2)+(\left(b+d\right)i)/(2)`

`M=(\left(-2+3\right))/(2)+(\left(-3+\left(9\right)\right)i)/(2)`

`M=(-2+3+\left(-3+9\right)i)/(2)`

`M=(1+6i)/(2)`

`M=(1)/(2)+3i`

Therefore, 1/2 + 3i is the midpoint between -2-3i and 3+9i.