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How high of a Frequency would a photon have to be for it to have an energy of 4 joules

User Amnesia
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1 Answer

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The frequency of photon=6.03 x 10³³ /s

Further explanation

Radiation energy is absorbed by photons

The energy in one photon can be formulated as


\large{\boxed{\bold{E\:=\:h\:.\:f}}}

Where

h = Planck's constant (6,626.10⁻³⁴ Js)

f = Frequency of electromagnetic waves

Energy of photon = 4 J

So the frequency :


\tt f=(E)/(h)\\\\f=(4)/(6.626.10^(-34))\\\\f=6.03.10^(33)/s

User Medkhelifi
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